3[x-2(x-5)]-1=-3x+29

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Solution for 3[x-2(x-5)]-1=-3x+29 equation: 


Simplifying
3[x + -2(x + -5)] + -1 = -3x + 29

Reorder the terms:
3[x + -2(-5 + x)] + -1 = -3x + 29
3[x + (-5 * -2 + x * -2)] + -1 = -3x + 29
3[x + (10 + -2x)] + -1 = -3x + 29

Reorder the terms:
3[10 + x + -2x] + -1 = -3x + 29

Combine like terms: x + -2x = -1x
3[10 + -1x] + -1 = -3x + 29
[10 * 3 + -1x * 3] + -1 = -3x + 29
[30 + -3x] + -1 = -3x + 29

Reorder the terms:
30 + -1 + -3x = -3x + 29

Combine like terms: 30 + -1 = 29
29 + -3x = -3x + 29

Reorder the terms:
29 + -3x = 29 + -3x

Add '-29' to each side of the equation.
29 + -29 + -3x = 29 + -29 + -3x

Combine like terms: 29 + -29 = 0
0 + -3x = 29 + -29 + -3x
-3x = 29 + -29 + -3x

Combine like terms: 29 + -29 = 0
-3x = 0 + -3x
-3x = -3x

Add '3x' to each side of the equation.
-3x + 3x = -3x + 3x

Combine like terms: -3x + 3x = 0
0 = -3x + 3x

Combine like terms: -3x + 3x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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